Decision Making
Statements in C. This post for Computer ICS Part 2 | Computer Science 2nd Year Chapter No.11
Decision Constructs. Find
the solution to all exercise questions in C language. Following exercise
programs in C are important for the final exams.
Chapter No.11: Decision Constructs
Exercise Programs
Q.8: Write an interactive program that contains an if statement that may
be used to compute the area of a square `(area=side^2)` or a triangle `(area=1/2\times base \times height)` after prompting the user to type the first character of the figure
name (S or T).
Answer:
#include<stdio.h>
#include<conio.h>
void main(void)
{
char ch;
float area,side,base,height;
printf("Enter S:area of square T:area of triangle:");
ch=getche();
if(ch=='S' || ch=='s')
{
printf("\nEnter the
value of side of square:");
scanf("%f",&side);
area=side*side;
printf("\nArea of
Square:%.2f", area);
}
else if(ch=='T' || ch=='t')
{
printf("\nEnter the
value of base of triangle:");
scanf("%f",&base);
printf("\nEnter the
value of height of triangle:");
scanf("%f",&height);
area=(base*height)/2.0;
printf("\nArea of
Triangle:%.2f", area);
}
else
printf("\nWrong
choice...\n\t\t Please enter S or T");
}
Q.9: A year is a leap year if it is divisible four, except that any year
divisible by 100 is a leap only if it is divisible by 400. Write a program that
inputs a year such as 1996, 1800, and 2010, and displays “Leap year” if it is a
leap year otherwise displays “Not a leap year”.
Answer:
#include<stdio.h>
#include<conio.h>
void main(void)
{
int year;
printf("\tEnter Year=");
scanf("%d",&year);
if(year%4==0)
printf("\n\t%d is a
Leap Year! ",year);
else
printf("\n\t%d is
not a Leap Year!",year);
}
Q.10: Write a program that inputs temperature and displays a message
according to the following data:
|
Temperature |
Message |
|
Greater than 35 |
Hot day |
|
Between 25 and 35 (inclusive) |
Pleasant day |
|
Less than 25 |
Cool day |
Answer:
#include<stdio.h>
#include<conio.h>
void main(void)
{
int temp;
printf("\t\tEnter temperature=");
scanf("%d",&temp);
if(temp>35)
printf("\n\tHot day!
");
else if(temp>=25
&& temp<=35)
printf("\n\tPleasant
day!");
else
printf("\n\tCool day
!");
}
Q.11: Write a program that inputs obtained marks of a student, calculate the percentage (assume total marks are 1100), and displays his/her grade. The grade should be calculated according to the following rules:
|
Percentage |
Grade |
|
More than or equal to 80 |
A+ |
|
Between 70 (inclusive) and 80 |
A |
|
Between 60 (inclusive) and 70 |
B |
|
Between 50 (inclusive) and 60 |
C |
|
Between 40 (inclusive) and 50 |
D |
|
Between 33 (inclusive) and 40 |
E |
|
Less than 33 |
F |
Answer:
#include<stdio.h>
#include<conio.h>
void main(void)
{
int obt_marks;
float page;
printf("Enter Obtained Marks = ");
scanf("%d",&obt_marks);
page=(obt_marks*100)/1100;
printf("\n\tPercentage : %.0f",page);
if(page>=80)
printf("\n\tGrade:
A+");
else if(page>=70
&& page<80)
printf("\n\tGrade:
A");
else if(page>=60
&& page<70)
printf("\n\tGrade:
B");
else if(page>=50
&& page<60)
printf("\n\tGrade:
C");
else if(page>=40
&& page<50)
printf("\n\tGrade:
D");
else if(page>=33
&& page<40)
printf("\n\tGrade:
E");
else
printf("\n\tF");
}
Q.12: Write a program that inputs two numbers and asks for the choice of
the user, if user enters 1 then displays the sum of numbers, if user enters 2
then displays result of subtraction of the numbers. If user enters 3 then
displays the result of the multiplication of the numbers and if user enters 4
then displays result of the division of the numbers (divide the larger number
by the smaller number), otherwise displays the message “Wrong Choice”. [Use a
switch statement to implement the solution]
Answer:
#include<stdio.h>
#include<conio.h>
void main(void)
{
int choice;
float a,b;
printf("Enter First No.?");
scanf("%f",&a);
printf("\nEnter Second No.?");
scanf("%f",&b);
printf("\nEnter 1:Additiona, 2:Subtraction, 3:Multipliation,
4:Division?");
scanf("%d",&choice);
switch(choice)
{
case 1:
printf("\n\tAddition
Result=%.2f\n\n",a+b);
break;
case 2:
printf("\n\tSubtraction
Result=%.2f\n\n",a-b);
break;
case 3:
printf("\n\tMultiplication
Result=%.2f\n\n",a*b);
break;
case 4:
if(a>b)
printf("\n\tDivision
Result=%.2f\n\n",a/b);
else
printf("\n\tDivision
Result=%.2f\n\n",b/a);
break;
default:
printf("\n\tWrong choice...");
}
}
The following may relate to you!
➤ Decision Constructs - Short Questions
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